之前写过nginx反代替换的教程（传送门），使用了ngx_http_substitutions_filter_module模块。不过这货只能替换同一行，具有局限性-_-#
现在一个更强大的替换模块来了……replace-filter-nginx-module
下面只翻译一下，再加个安装教程，因为我自己也没弄懂怎样玩= =
1.安装此模块需要先安装sregex运行库
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apt-get update;apt-get install git make gcc -y #Centos改成yum git clone https://github.com/agentzh/sregex cd sregex make make install cd .. git clone https://github.com/agentzh/replace-filter-nginx-module wget http://nginx.org/download/nginx-1.2.6.tar.gz tar zxvf nginx-1.2.6.tar.gz cd nginx-1.2.6 ./configure --add-module=../replace-filter-nginx-module #自行加其他编译参数 make make install |
nginx.conf的用法举例：
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location /t { default_type text/html; echo abc; replace_filter 'ab|abc' X; } location / { # proxy_pass/fastcgi_pass/... # caseless global substitution: replace_filter '\d+' 'blah blah' 'ig'; replace_filter_types text/plain text/css; } |
Syntax语法：
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^ 匹配起始行数 $ 匹配末尾行数 \A match only at beginning of stream \z match only at end of stream \b match a word boundary \B match except at a word boundary . match any char \C match a single C-language char (octet) [ab0-9] character classes (positive) [^ab0-9] character classes (negative) \d match a digit character ([0-9]) \D match a non-digit character ([^0-9]) \s match a whitespace character ([ \f\n\r\t]) \S match a non-whitespace character ([^ \f\n\r\t]) \h match a horizontal whitespace character \H match a character that isn't horizontal whitespace \v match a vertical whitespace character \V match a character that isn't vertical whitespace \w match a "word" character ([A-Za-z0-9_]) \W match a non-"word" character ([^A-Za-z0-9_]) \cK control char (example: VT) \N match a character that isn't a newline ab concatenation; first match a, and then b a|b alternation; match a or b (a) capturing parentheses (?:a) non-capturing parantheses a? match 1 or 0 times, greedily a* match 0 or more times, greedily a+ match 1 or more times, greedily a?? match 1 or 0 times, not greedily a*? match 0 or more times, not greedily a+? match 1 or more times, not greedily a{n} match exactly n times a{n,m} match at least n but not more than m times, greedily a{n,} match at least n times, greedily a{n}? match exactly n times, not greedily (redundant) a{n,m}? match at least n but not more than m times, not greedily a{n,}? match at least n times, not greedily |
作者信息：
Yichun "agentzh" Zhang (章亦春) [email protected]
你的翻译哪下面那些替换规则类似php使用正则和直接替换的感觉可惜你换了多说 不然刷评论看看你博客会不会404 嗯
不换多说不行。。。太蛋疼了。。。。
test
懒得玩反带了。。。
不一定要反代的嘛。。。
求带，杂弄？
本机玩= =